• MS Dhoni has stepped down as captain of India's  ODIs and T20Is .He will be avalible as wicketkeeper-batsman for the series

• India win record 4th straight SAFF Women's C'ship title 

• Veteran actor Om Puri passes away at 66 

• Japan to help develop Chennai, Varanasi as smart city

• Donald Trump appoints Indo-American to key White House post 

• Guwahati's first Braille library opens

• World record for largest tennis lesson set at Chennai Open

• China launches its longest bullet train 

• Sitharaman launches IPR Enforcement Toolkit for police

• S Padmanabhan nominated as Tata Power chairman

• Capgemini appoints IBM’s Anil Jalali as India HR head                     
• SIDBI ties up with LIC for capital support to enterprises 

On a man's tombstone, it is said that one sixth of his life was spent in childhood and one twelfth as a teenager. One seventh of his life passed between the time he became an adult and the time he married; five years later, his son was born. Alas, the son died four years before he did. He lived to be twice as old as his son did. How old did the man live to be?

what is the maximum value of x^3y^3+3x*y
when x+y=8

We have an equal arms two pan balance and need to weigh objects with integral weights in the range 1 to 40 kilo grams. We have a set of standard weights and can place the weights in any pan. . (i.e) some weights can be in a pan with objects and some weights can be in the other pan. The minimum number of standard weights required is:
a. 4
b. 10
c. 5
d. 6 

Option a) 4 → three std weights of 2 kg each and one std wt. of 5 kg 

We just need to factorize the magnitude of the highest weight, i.e., 40. 

40 = 2x2x2x5 

to weigh 1kg → 2x2 kg in one pan and 5 on the other 

to weigh 3 kgs → 2 kg in one pan and 5 kg on the other, and so on.

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If n is the sum of two consecutive odd integers and less than 100, what is the greatest possibility of n?
a)98
b)94
c)96
d)99

aking greatest possibility
we take 51 + 49 but 51 + 49 = 100, we need x + y < 100
so we take 47 + 49 = 96 (ANS)

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A call center agent has a list of 305 phone nos of people in alphabetic order of names (but she does not have any of the names). she needs to quickly contacts deepak sharma to convey a message to him.If each call takes 2 minutes to complete, and every call is answered, what is the minimum amount of time in which she can guarantee to deliver the message to Mr.Sharma.

t is actually based on Binary search. Since, the numbers are in alphabetical order of names, she can call the last number and ask his name. Based on the response, she picks up 305/2 = 152 nd number. Then, 152/2 = 76 th number, then 76/2 = 38th number, 38/2 = 19 th number, 19/2 = 9th number, 9/2 = 4th number, 4/2 = 2nd number, 2/2 = 1st number. So, she has to make minimum 9 calls. Each call duration is 2 minutes. So, she takes 18 minutes.

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Eric throws two dice, and his score is the sum of the values shown. Sandra throws one die, and her score is the square of the value shown. What is the probability that Sandra’s score will be strictly higher than Eric’s score?

A. 137/216 b. 17/36 c. 173/216 d. 5/6

A. 137/216

Sandra's possible scores-
1 (1)
4 (2)
9 (3)
16 (4)
25 (5)
36 (6)

So for Sandra's score=1 there will be no favorable outcomes as Eric score will always be >=2 with 2 being his least score for dice throws of 1 and 1 on both dice.

Similarly for X=4 (Sandra's score)
Dices throw of (1,1) , (1,2) , (2,1) are favorable cases.
so P(X=4)= 3/36* 1/6= 3/216
[ 1/6 is the probability of getting 2 on a throw of dice by Sandra (and hence the score=4) and 3 outcomes are favorable out of 36 for Eric's throw of 2 dice.

Same with X=9
Favorable Cases- (1,1), (1,2) ,(1,3) ,(1,4) ,(1,5) ,(1,6) ,(2,1) ,(2,2) ,(2,3) ,(2,4) ,(2,5) ,(2,6) ,(3,1) ,(3,2) ,(3,3) ,(3,4) ,(3,5) ,(4,1) ,(4,2) ,(4,3) ,(4,4) ,(5,1) ,(5,2) ,(5,3) ,(6,1) ,(6,2)
so P(X=9)= 26/36*1/6 = 26/216

For X=16, 25,36
all cases are favorable as the max score of Eric can be 12 (6,6)
Hence P(X=16)=P(X=25)=P(X=36)= 1/6* 36/36=36/216

So adding all the cases-
3/216 + 26/216 + 36/216 +36/216 + 36/216 = 137/216 (Ans)

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Which is the largest integer that divides all three numbers 23400,272304,205248 without
leaving a remainder?
a. 48
b. 24
c. 96
d. 72

h.c.f. of 48,24,96,72 is 24 

how?
48=2^4*3
24=2^3*3
96=2^5*3
72=2^3*3^2

so, h.c.f is 2^3*3=24

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What is the largest number that will divide 90207, 232585 and 127986 without leaving a
remainder?
a) 257 b) 905 c) 351 d) 498 

232585 - 127986 =104599
127986 - 90207 = 37779

since 37779 < 104599

v use 37779
1st 37779/257=147
37779/905=41.74....
37779/351=107.6....
37779/498=75.8....

so ans is 257

we understand that answer is the HCF of all the numbers, but we need not to actually calculate the HCF, just a little observation will help you to get through in seconds by reducing the options.. first check the numbers, and the options, as 498 is one of the options, that means, all the numbers should be even number as 498 is also an even number, but only 127986 is even so 498 is not the option, then we check the divisibility by 3, so 232585 is not divisible by 3, that means amongst the options, one which is divisible by is not the correct one, 351 is not the answer, then for being divisible by 905, numbers should be divisible by 5 as well, but only 232585 is divisible...so 905 is also not the correct answer, so we are left with 257 as correct answer... :) :)

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What is the distance of BC in cms if two circles of radii 5 cm and 3 cm touch each other at A and also touch a line at B and C?

If r1, r2 are the radii of two circles and d is distance between their centers, then
 (i) the length of a direct common tangent =

 (ii) the length of a transverse common tangent =

Thus, 60^0.5

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In the polynomial f(x) = x^5 + a*x^3 + b*x^4 +c*x + d, all coefficients a, b, c, d are integers. If 3 + sqrt(7) is a root, which of the following must be also a root?(Note that x^n denotes the x raised to the power n, or x multiplied by itself n times. Also sqrt(u) denotes the square root of u, or the number which when multiplied by itself, gives the number u)?

a. 3-sqrt(7)

b. 3+sqrt(21)

c. 5

d. sqrt(7) + sqrt(3)

Sol: Option A

here, 
taking option a.
sum of roots=(-a/1)=(3+sqrt7)+(3-sqrt7)=6....therefore a=-6(an integer value)
and product of roots=(-d/1)=(3+sqrt7)(3-sqrt7)=9-7=2....therefore d=-2(an integer value)
No other options satisfy the condition of a and d to be integer values.